输入:nums1 = [4,1,2], nums2 = [1,3,4,2]
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* 时间复杂度:O(n),空间复杂度:O(1)
The critical thing to understand is namespaces are visibility walls, not security boundaries. They prevent a process from seeing things outside its namespace. They do not prevent a process from exploiting the kernel that implements the namespace. The process still makes syscalls to the same host kernel. If there is a bug in the kernel’s handling of any syscall, the namespace boundary does not help.
// not critical but safer when bytesToWrite != view.byteLength